moe
|
| posted on 12/8/04 at 10:15 AM |
|
|
Panhard rod
Hello there
I happened upon this site whilst looking for someone to make me up a panhard rod and wondered whether anyone can recommend a company to me, preferably
in the South/South-West.
I've recently fitted lowering springs to my vehicle (Daiahtsu Avanzato TRXXR4) and need a new rod making up, as the one on my vehicle is not
adjustable.
Any help/recommendations would be greatly appreciated
Regards
Matt
|
|
|
|
|
Peteff
|
| posted on 12/8/04 at 10:39 AM |
|
|
Panhard rod adjustment.
What size are the ends and what is the rod made of. You could cut the present one and fit a spherical rod end to one end to give you some adjustment
or you could use a left and right handed joint at each end so you can adjust it in situ. Most on here have made their own from cds tubing with either
poly bushes or rod end bearings.
yours, Pete
I went into the RSPCA office the other day. It was so small you could hardly swing a cat in there.
|
|
|
moe
|
| posted on 12/8/04 at 01:16 PM |
|
|
To be honest I'm not too hot on DIY engineering (in other words I haven't got a clue!) and would just like a reliable company to make me
one up.
The main thing that's bugging me is how I would work out what length it needs to be, taking into account the 30mm or so it's been lowered.
Is there a calculation I can use?
Regards
Matt
|
|
|
MikeRJ
|
| posted on 12/8/04 at 02:15 PM |
|
|
Idealy you should move the chassis mounting point 30mm upwards as well. This will ensure the panhard rod stays as near horizontal as possible under
static conditions, and the sideways thrust on the axle as it moves up and down will be minimised. The panhard rod also stays the same length.
With the suspension lowered as it is, the panhard rod sits at an angle. This makes it impart a sideways motion to the axle as it moves up and down.
That said, if the panhard rod is very long compared to the 30mm drop, and is close to horizontal there shouldn't be a problem.
You can calculate the new length required very simply using pythagorus theorum. Imagine the chassis mounting point and the old and new locations of
the axle mounting point forming a triangle
code:
New axle location
o
o o
Old axle location Chassis mounting point
y = SQR( x^2 + 30^2 )
Where:
y=new length of panhard rod in mm
x= original length of panhard rod in mm
SQR = square root
^2 = squared (raised to power of 2).
e.g if the rod was 1000mm long:
SQR(1000^2 + 30^2) = 1000.45mm
Only half a mm longer, and certainly not worth bothering with. The shorter the panhard rod, the bigger the difference will be.
[Edited on 12/8/04 by MikeRJ]
|
|
|
