Hi all,
a chap in work is doing some maths and is stuck on this. I said I would have a look but I cannot remember how to do these. Maths was too many moons
ago for me.
Anyone know how to do it or what type of problem it is so I can have a go.
Cheers,
y=((a+x)/(5-bx))
[Edited on 18/3/16 by emsfactory]
[Edited on 18/3/16 by emsfactory]
Looks like a quadratic equation, so easy I'll let someone else do it
y=((a+x)/(5-bx))
5y-ybx=a+x
5y-ybx-a=x
5y-a=x+ybx
5y-a=x(1+yb)
x=(5y-a)/(1+yb)
does that work? been a while (30 years...)
I love a bit of algebra.
A quick scribble suggests
X = (5y-a) /(yb+1)
Damn too slow! Thats how i did it as well.
[Edited on 18/3/16 by bi22le]
Yeah thats where we got too. I am thinking there is more to it though. Some formula to be applied to make it nicer.
would need y a and b values to.input.if he wants a numerical value of x
x=(5y-a)/(1+yb)
This is as far as you can take it unless you start with derivatives
then it becomes
(d)/(dx)((a+x)/(5-b x)) = (a b+5)/(b x-5)^2
Presumably a and b are constants, x and y are variables.
You have too many unknowns to solve this equation, but:
when y = 0, x = -a
when x = 0, y= a/5
Given values for the constants a and b, you could then draw a graph of the equation - it's linear, so should be a straight line.
quote:
Originally posted by jonrotheray
Presumably a and b are constants, x and y are variables.
You have too many unknowns to solve this equation, but:
when y = 0, x = -a
when x = 0, y= a/5
Given values for the constants a and b, you could then draw a graph of the equation - it's linear, so should be a straight line.
pies are the answer,beef lamb,steak and kidney kidney,chicken..............................just pies
Nope thats it. You cant simplify it.