omega 24 v6
|
posted on 4/12/13 at 09:16 PM |
|
|
quick Anglia question
What is the bore and stroke of an Anglia clutch slave cylinder. I'm presuming theres only one size but not 100% sure.
If it looks wrong it probably is wrong.
|
|
|
britishtrident
|
posted on 4/12/13 at 09:28 PM |
|
|
If it is the original circlip type 0.625"" bore then it can be swapped for a Lotus Elan one which has a bigger bore
0.875" which gves lighter pedal but gears can be difficult to engage when stationary.
A 3/4" bore will also exist MK1 Cortina ?
The clutch slave cylinder change completely between Mk1 and Mk2 Cortinas.
The Anglia/Mk1 Cortina/Lotus Elan clutch fork assembly and release bearing was a pain in the ass.
[Edited on 4/12/13 by britishtrident]
[I] “ What use our work, Bennet, if we cannot care for those we love? .”
― From BBC TV/Amazon's Ripper Street.
[/I]
|
|
omega 24 v6
|
posted on 4/12/13 at 09:35 PM |
|
|
Its for my cousins angle box sprint/hill climb motor. Trouble is its 150 miles away so I'm going on sizes given to me. Says the slave ( remember
its the slave we are talking about) is 22mm dia ( metric guestimate or measured as close as possible with what tools he has)
He has a 0.750 master cyl but is short on travel due to a modified pedal box. I've done all the fluid volume transfer calcs BUT fear that
without very accurate measurements they might not be accurate enough.
[Edited on 4/12/13 by omega 24 v6]
If it looks wrong it probably is wrong.
|
|
britishtrident
|
posted on 4/12/13 at 10:00 PM |
|
|
The standard Anglia slave will let the clutch clear but the pedal will be very heavy.
[I] “ What use our work, Bennet, if we cannot care for those we love? .”
― From BBC TV/Amazon's Ripper Street.
[/I]
|
|
omega 24 v6
|
posted on 4/12/13 at 10:04 PM |
|
|
Problem is B.T that its not disengaging. Given the sizes and travel at the master cyl AND the diameter/ possible travel on the slave he either needs
to modify the pedal box OR by my calcs go to a .825 master and will need legs like a russian weightlifter.
If it looks wrong it probably is wrong.
|
|