I have coil of water cooled copper tubing - 5 turns that I use as an induction heater.

As part of the process I need to disconnect the coil from the high frequency induction heater supply and feed in a dc current to create a magnetic field.

Trouble is I need over 100A feeding into a dead short. Also I need to do it for hours.....

Will a TIG welder feed into a short continuously or will the welder self destruct?

Cheers!

you will hit the duty cycle pretty quickly, also most tigs are low volts high amps.

Cool

You want super low volts as all the voltage drop (and hence heat) will be across the amplifier.
Amplifier from an MRI scanner would do the job for you, but outside your price range.


If you split your single loop into 4 parallel loops then you could wire them in series for the DC (25A) and in parallel for the AC.
Just a thought.

Matt

Ta chaps,

I can buy a power supply for £6k but that's 25% of my total budget

I want high amps low volts and that's what a tig welder gives?

At 100A the volt drop across the load is 2.5V is this within welder specs?

Cheers!

http://www.youtube.com/watch?v=uXEPy6Za6cI

add a decent rectifier to the thing in the link above and it would do it for weeks

Been thinking about you power requirements today.

Have a look at 3.3V computer power supplies.
The often have high current outputs.

Found this at Farnell. (£300)
LINK
Claims 2.64 to 3.3V at 120A.
Bit near the limit for reliability, but there may well be bigger PSU's that would work, Even if you had to lose 1V through a resistor.
1 volt at 120A is only 120W
2off 100W resistors would be no more the £10.



Even 10 PC PSU's in parallel would give 200A at 3.3V for £150
If they could be joint using low ohm 50W resistors it way well work, just a bit amateurish.

quote:

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Originally posted by rf900rush
Been thinking about you power requirements today.

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