Guys, in US bingo the card has 25 numbers and the numbers called go from 1 to 75.

Question..what are the odds of getting a full card (house) within 54 numbers or less?

[Edited on 6/2/08 by Alan B]

too high for me, I don't bet

slim?

Erm......thanks guys....rather hoping for something a little more numerical...

I agree though...it's got to be pretty high.

1 in 347,916

That do for you Alan?

I used no sound mathematical basis to arrive at this figure, but it is more numerical than my previous guess

there is a super simple way of doing this

let me think for a minute

1 in 4050???

Steve

The probability within 54 calls is:

combin(75-25,54-25)/combin(54,54)

combin(k,n) = n! / (k! (n-k)! )

tehn again maybe it isn't.

quote:

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Originally posted by 02GF74
The probability within 54 calls is:

combin(75-25,54-25)/combin(54,54)

combin(k,n) = n! / (k! (n-k)! )

tehn again maybe it isn't.

---

060208

That's just showing off that is

Roughy 5.2X10 to the 19.

Using 75!/(25!*(75-25)!)

I hope thats clear.

Basicaly you have a greater chance of getting pregnant. Assuming you're male.

Erm hold on. Thats wrong. Read the question! doh.

Right tried to remember how to do this but can't right now. You need to use permutations and combinations. Have a look at your calculator the nCr button does it. If you do 75 choose 25 that gives you the above answer which is slim. Meaning the first 25 numbers are your numbers. You would have a better chance if you had 54 tries but don't know how to account for that.

[Edited on 6/2/08 by joneh]

[Edited on 6/2/08 by joneh]

[Edited on 6/2/08 by joneh]

[Edited on 6/2/08 by joneh]

the chance of a number chosen at random being on your card is 1 in 3. It stays at about that level if you cross 1 number off in every 3 that are called. To get all your numbers in the first 54, you need to average 1 in 2.16. It is less than likely. My statistics aren't good enough to work it out.

Thanks guys....she went anyway...

I'll let you know if she wins...$7k for a full house within 54 numbers..

IOW..last post on this thread by me....

Alan

Unashamedly stolen from http://www.saliu.com/bbs/messages/266.html but might help you work it out:

"The lotto games are much more diverse. The diversity widens when the 'power ball' games are taken into account. The lottery commissions set the odds as exactly k of m. Exactly is the operative word here. I thought it was at least. I started a heated debate in 2001, in newsgroups, thinking that the lottery commissions were dead wrong in their calculations of odds. I admit it, I was wrong, but for a right reason. The odds calculated as at least k of m lead to very different values.
The most certain element in calculating the lotto odds is total possible cases. It is known as total number of combinations C(n, k). The combination formula is widely accepted, expert or not.


n!
C(n, k) = --------------

k! (n – k)!

or

n*(n-1)*(n-2)*(n-3)*...(n-k+1)

C(n, k) = -------------------------------------

1*2*3*...k

n! represents the factorial and is calculated as 1*2*3*4*...*n. For example, the lotto 6/49 game has a total of [49 * 48 * 47 * 46 * 45 * 44] / [1 * 2 * 3 * 4 * 5 * 6] = 13,983,816 combinations.
I wrote software to do all the calculations, accurately and freely: ODDS.EXE and ODDSCALC.EXE.
ODDSCALC.EXE calculates the odds of any lotto game, including power ball and keno. If the game draws 6 winning numbers, the program calculates the odds from '0 of 6' to '6 of 6'. Of course, '6 of 6' represents the jackpot case.
ODDS.EXE calculates the lotto odds using the 'hypergeometric distribution probability'. The odds are calculated as 'k of m in n from N'. More clearly, let's suppose a lotto 6/49 game. The lottery draws 6 winning numbers. The player must play exactly 6 numbers per ticket. But the player can choose to play a pool of 10 favorite numbers. What is the probability to get '4 of 6 in 10 from 49'? The odds: '1 in 90'. "

Hope this helps

ATB

Simon

bingo is rather different to lotto games.

I don't frequent bingo halls but I thought that the game ends when there is a full house? Therefore it depends on the number of boards that are entered in that specific bingo game.