simonwinn
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| posted on 2/11/10 at 08:27 PM |
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Way OT Homework help
Ok for the first time since leaving school some 15 years ago im stuck. So I thought I'd ask you lot as someone always seems to know the answer
to every question asked. Here goes,
Draw a scaled phasor diagram to determine the equation for the resultant wave formed by adding the following 2 waves:
V1=12 Sin 314t
V2=8 Sin(314t +Pi/3)
I think ive got the resultant phasor to be 17.44 but the angle come to 23.41DEG but need to display as a proportion of pi.
Any suggestions..
Ah the forum doesnt like pi, hmm.
[Edited on 2/11/10 by simonwinn]
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stevegough
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| posted on 2/11/10 at 08:30 PM |
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six.
Luego Locost C20XE.
Build start: October 6th 2008.
IVA passed Jan 28th 2011.
First drive Feb 10th 2011.
First show: Stoneleigh 1st/2nd May 2011.
'Used up' first engine may 3rd 2011!
Back on the road with 2nd engine may 24th
First PASA mad drive 26/7/11
Sold to Mike in Methyr Tydvil 19/03/14
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bi22le
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| posted on 2/11/10 at 09:35 PM |
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42 ( the meaning of life)
Like your ever going to need that in life!!!
Good luck, come on LCB somebody must know?!!!
Track days ARE the best thing since sliced bread, until I get a supercharger that is!
Please read my ring story:
http://www.locostbuilders.co.uk/forum/13/viewthread.php?tid=139152&page=1
Me doing a sub 56sec lap around Brands Indy. I need a geo set up! http://www.youtube.com/watch?v=EHksfvIGB3I
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Ninehigh
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| posted on 2/11/10 at 10:19 PM |
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Blue Whale!
(sorry I haven't an effing clue what you're asking, but I did understand pie)
(I feel really thick now)
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markt0121
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| posted on 2/11/10 at 10:27 PM |
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2 x Pi = 360 degrees
Did you not use that to draw the phase offset of V2 on your phasor diagram?
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Peteff
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| posted on 2/11/10 at 11:12 PM |
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MMMMmmmm pie.
yours, Pete
I went into the RSPCA office the other day. It was so small you could hardly swing a cat in there.
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Liam
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| posted on 3/11/10 at 01:06 AM |
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Mmmmmmmmmmmmm pie.
Looks right to me, so the equation they're asking for (with phase angle in radians - so 23.41 x (PI/180) = 0.41rad) would be...
V = 17.44sin(314t + 0.41)
That what you mean? Not sure what you mean by 'display as a proportion of PI', but if you must...
V = 17.44sin(314t + 0.13PI)
or even
V = 17.44sin(314t + PI/7.7)
but not sure why you'd want to express it that way.
I'm very rusty - could all be bollards 
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02GF74
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| posted on 3/11/10 at 10:38 AM |
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quote:
Originally posted by simonwinn
the angle come to 23.41DEG but need to display as a proportion of pi.
Any suggestions..
can't say I understand most of that but as you asking what 23.41 deg is in term of pie?
360 = 2 pi degrees so you have
23.41/360 x 2 pi or 0.13 pi
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scudderfish
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| posted on 3/11/10 at 10:42 AM |
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http://www.wolframalpha.com/input/?i=V1%3D12+Sin(pi+*+t)+%2B+8+Sin(pi*+t+%2BPi/3)+
Have a play with that
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simonwinn
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| posted on 3/11/10 at 04:51 PM |
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Thanks for the help guys.
V = 17.44sin(314t + PI/7.7) was the one the tutor was asking for, he would also of taken .41.
This is supposed to be as hard as it gets, I hope hes right as I'm only 2 months into the apprenticeship..
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Ninehigh
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| posted on 3/11/10 at 04:56 PM |
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What are you doing rocket science?
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simonwinn
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| posted on 3/11/10 at 06:22 PM |
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3 year Maintenance Engineering Apprenticeship at the Toyota Factory near Derby.
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